Question

Let \\(E=t { x|x^{2}-3x=-2 }\\), \\(H=t { 1,2 }\\). Then

Answer 1

Step-by-step explanation:

Question is inappropriate.. Kindly repost

Answer 2

Answer:

$E \subseteq \: H \\ or \\ H \subseteq \: E$

Step-by-step explanation:

To find the relation between set E and H,first convert set E in the roster form.

${x}^{2} - 3x = - 2 \\ \\ {x}^{2} - 3x + 2 = 0 \\ \\ {x}^{2} - 2x - x + 2 = 0 \\ \\ x(x - 2) - 1(x - 2) = 0 \\ \\ (x - 2)(x - 1) = 0 \\ \\ so \\ \\ x = 2 \\ \\ or \\ \\ x = 1$

Set E ={2,1}

Set H= {1,2}

Both E and H are equal sets.

or

$E \subseteq \: H \\ \\ or \\ \\ H \subseteq \: E$

Hope it helps you.