Question

Let equations of line PQ, PR and QR are 2x-y-2 = 0, 4x + 3y = 24 and y + 4 = 0 respectively then find the length of perpendicular drawn from ventes P
on QR​

Answer 1

Answer:

The answer is 8 units

Step-by-step explanation:

PQR is a Triangle and the equations of its sides have been given.

P is the point of intersection of PQ and PR and solving

PQ => 2x-y=2 and PR => 4x + 3y = 24 we get P(3,4)

Perpendicular between the Point P and line QR is given as

Length of perpendicular => $\frac{| ax + by + c| }{\sqrt{a^2 + b^2} }$

Equation of QR => 0x + y + 4= 0 and P(3,4)

Hence the length of the perpendicular is

$\frac{| 4 + 4|}{\sqrt{0^2 + 1^2} } = 8 units$