Question

Let f:{(1, 1), (2, 3), (0, -1), (-1, -3)} be a function from z to z defined by f(x) = ax +b, for some integers a, b then (a, b)=
1) (-1, 2) 2) (2, -1) 3) (3, -2) 4) (0, 3)

Answer 1

Answer:

Step-by-step explanation:

f={(1,1),(2,3),(0,−1),(−1,−3)}

f(x)=ax+b

(1,1)∈f

⇒f(1)=1

⇒a×1+b=1

⇒a+b=1     ...(1)

(0,−1)∈f

⇒f(0)=−1

⇒a×0+b=−1

⇒b=−1

On substituting b=−1 in eqn (1), we get

a+(−1)=1

⇒a=1+1=2

Thus the respective values of a and b are 2 and −1

Answer 2

Answer:

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