Let f = { (1,1) , (2,3) , (0,-1) , (-1,-3) } be a linear function from Z toZ . Find f(x).
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Since f is a linear function.
Let f(x)=mx+c
x y y=mx+c (1,1) 1 1 1=m×1+c⇒1=m+c (2,3) 2 3 3=m×2+c⇒3=2m+c
Solving m+c=1 .....(1)
2m+c=3 .......(2)
Equation (2)−(1)
⇒2m+c−(m+c)=3−1
⇒2m+c−m−c=2
⇒m=2
Put m=2 in (1)
m+c=1
⇒2+c=1
⇒c=1−2=−1
So,f(x)=mx+c=2x−1
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