let f= (1 4) ,(2 5),(3 6) ,(4 k) is a linear function then find the value of function and value of k
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let f(x)=ax+b=y
at (1,4) = a(1)+b=4
= a+b=4 --------- (1)
at (2,5) =a(2)+b=5
= 2a+b=5 ----------(2)
subract (1) &(2)
-a - b = -4
-2a -b = -5
= -3a =-9
a= -9/-3
a=3.
From (1) &(3)
a+b=4
3 + b =4
b=4-3
b= 1.
now f(x) =x+3
at (4,k)
k= 4+3
k= 7
therefore (4,7)
Step-by-step explanation:
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