Question

Let f:[−2,2]→R be a continuous function such that f(x) assumes only irrational values. If f(
$\sqrt{2 }) = \sqrt{2}$
, then

A .

f(0)=0

B .

f(2​−1)=2½​−1

C .

f(2​−1)=2​½+1

D .

f(2​−1)=2​½

​

Answer 1

Step-by-step explanation:

If a function f(x) assumes only irrational values which is also continuous, then f(x) must be a constant function.

⇒F(x)=√2

⇒[F(√2)=√2]

=F(√2-1)-√2

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