Let f:[a,b] → then f(x) is said to be bounded for some positive real number A and
Vxe[a,b]
O ]
O |
Of(x)2-A
|f(x)/2A
f(x) s-A
|f(x) sa
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The correct answer is option (b) f(x)/2A.
Explanation:
- Let f:[a,b] → then f(x) is said to be bounded for some positive real number A and Vxe[a,b] is f(x)/2A.
- A bounded function f on [a, b] is referred to be (Riemann) integrable if L(f) = U(f).
- Suppose f is a non-negative function defined on the interval [a, b].
- Since f is bounded, there exist real numbers m and M such that m ≤ f(x) ≤ M.
- Hence, the correct answer is option b() f(x)/2A.
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