Question

Let f:A->B,g:B->C be bijection.Then show that gof:A->C is a bijection​

Answer 1

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Answer 2

ANSWER:-

$\longrightarrow$$\sf\red{Suppose \: gof(x1) = gof(x2)}$

$\longrightarrow$$\sf\red{g(f(x1)) = g(f(x2))}$

$\longrightarrow$$\sf\red{f(x1) = f(x2)as \: g \: is \: one \: one}$

$\longrightarrow$$\sf\red{x1 = x2\: is \: f \: is \: one \: one}$

$\longrightarrow$$\sf\pink{Hence\:gof\:is\:one-one}$