Question

let f be a function defined by f(x) =5x^2 +2,x belongs to R . find alpha such that f(alpha) =22​

Answer 1

Answer:

$\red { Value \: of \: \alpha } \green { = ±2}$

Step-by-step explanation:

Let f be a function defined by f(x) =5x^2 +2,x belongs to R

$f(\alpha) = 22 \:(given)$

$\implies 5\alpha^{2} + 2 = 22$

$\implies 5\alpha^{2} = 22 - 2$

$\implies 5\alpha^{2} = 20$

$\implies \alpha^{2} = \frac{20}{5}$

$\implies \alpha^{2} = 4$

$\implies \alpha = ± \sqrt{4} \\= ±2$

Therefore.,

$\red { Value \: of \: \alpha } \green { = ±2}$

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