Math, asked by aniketotari5458, 11 months ago

Let f be a function defined by f(x) =5x2++2,x belongs to R. Find a such that f(a) =22.

Answers

Answered by rucha247
1
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Answered by slicergiza
2

Answer:

The value of a is 2 or -2.

Step-by-step explanation:

Given function,

f(x) = 5x^2 + 2

Where, x ∈ R ( set of real number )

Put x = a

f(a) = 5a^2 + 2

According to the question,

5a^2 + 2 = 22

5a^2 = 20

a^2 = 4

a=\pm 2

Hence, the value of a is 2 or -2.

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