Question

Let f be a function , which is not continuous ,then f 2 is


(A) unique and distinct

(B) continuous

(C) discontinuous

(D) none of these​

Answer 1

Answer:

c)discontinuous

Step-by-step explanation:

I don't know that is perfect answer or not

Answer 2

Answer:

f(2) function will be continuous. So the correct option is (B) continuous.

Step-by-step explanation:

Let f(x) = $\left \{ {{1} \atop {-1}} \right.$ if x > 0

                     else

Then this function plainly exhibits a jump discontinuity at x = 0.

However, if |f(x)| = 1 is a continuous value.

In the above case, f²(x) = 1, therefore the function's multiplication on itself corrected any problems with my initial function moving from negative to positive. In other words, if a function's graph has no holes or breaks, it is continuous. It's simple to figure out where it won't be continuous for many functions. When we have things like division by zero or logarithms of zero, functions won't be continuous.

Thus, if a continuous function is defined differently in distinct intervals, it is said to be piecewise continuous.