Question

Let f be the mod 10 function, find f(417), f(38), f(253), f(316)

Answer 1

Answer:

It is given that 1 is mod-11 function. It means

f(x)= x(mod-11)

If x(mod-111-a, then a is remainder when x

is divided by 11.

(a)

f(417) = 417(mod-11)

(417) 10 If 417 is divided by 11,

then remainder is 10)

The value of f(417) is 10.

(b)

(40)-40(mod-11)

f(40)=7 (If 40 is divided by 11, then remainder is 7)

The value of f(40) is 7.

(c)

f(-253)-253(mod-11)

/(-253) 0 (If-253 is divided by 11.

then remainder is 0)

The value of f(-253) is 0.

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