Question

Let f.g, h:(-1,1) + R defined by f(x)
+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] then
f(x) is continuous but not differentiable on (-1,1)
f(x) is differentiable on (-1,1)
g(x) is continuous but not differentiable on (-1,1)
h(x) is strictly increasing function​

Answer 1

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$<font style="italics"><font color="red">$Let f.g, h:(-1,1) + R defined by f(x)

+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] then

f(x) is continuous but not differentiable on (-1,1)

f(x) is differentiable on (-1,1)

g(x) is continuous but not differentiable on (-1,1)

h(x) is strictly increasing function

Let f.g, h:(-1,1) + R defined by f(x)

Let f.g, h:(-1,1) + R defined by f(x)+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] then

Let f.g, h:(-1,1) + R defined by f(x)+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] thenf(x) is continuous but not differentiable on (-1,1)

Let f.g, h:(-1,1) + R defined by f(x)+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] thenf(x) is continuous but not differentiable on (-1,1)f(x) is differentiable on (-1,1)

Let f.g, h:(-1,1) + R defined by f(x)+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] thenf(x) is continuous but not differentiable on (-1,1)f(x) is differentiable on (-1,1)g(x) is continuous but not differentiable on (-1,1)

Let f.g, h:(-1,1) + R defined by f(x)+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] thenf(x) is continuous but not differentiable on (-1,1)f(x) is differentiable on (-1,1)g(x) is continuous but not differentiable on (-1,1)h(x) is strictly increasing function

Let f.g, h:(-1,1) + R defined by f(x)

+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] then

f(x) is continuous but not differentiable on (-1,1)

f(x) is differentiable on (-1,1)

g(x) is continuous but not differentiable on (-1,1)

h(x) is strictly increasing function

Let f.g, h:(-1,1) + R defined by f(x)

+ R defined by f(x) = xx g(x) = 1 xl, h(x) = x + [a] then

f(x) is continuous but not differentiable on (-1,1)

f(x) is differentiable on (-1,1)

g(x) is continuous but not differentiable on (-1,1)

h(x) is strictly increasing function