Question

Let f:N×N→N−{1} be defined as f(m,n)=m+n, then function f is ______.​

Answer 1

Answer:

Given f(m,n)=m+n

Range of this function is set of all natural numbers except 1

[since least value of m and n is 1]

Therefore the range and co-domain are equal

Therefore it is onto

For every (m,n), there exists only one m+n

Therefore it is one-one also

Hence, f is one-one and onto.

Answer 2

Answer:

Hey Mate The correct answer is One-One and onto

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