Question

Let f: R → R be a function given by f(x) = x ²+ 1 then the value of f‐¹ (26) is​

Answer 1

Answer:

Answer: f^-1(26)= 5

Step-by-step explanation:

f(x)=x^2+1

let y= x^2 + 1

y-1=x^2

x=√(y-1)--------(i) equation

f^-1(y)=√(y-1)

so, f^-1(26)=√(26-1)

=5