Let f:R → R be given by
f(x) = (x + 1)2 – 1, x>-1. Then the set of values
of x for which f(x) = f'(x) is given by
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helo guys its your answer
Step-by-step explanation:
(1) Solution: f(x)=x1+x2 f′(x)=(1+x)2⋅ 1−x⋅2x(1+x2)2=1−x2(1+x2)2 f'(x) changes(2)
2.1.2 Relations A Relation R from a non-empty set A to a non ... example f : R – {– 2} → R defined by f (x) = 1. 2 x x. +. +.
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