Math, asked by rknair6935, 11 months ago

Let f : R \rightarrow [0,∞) be such that \underset{x \rightarrow 5}{lim} f(x) exists and \underset{x \rightarrow 5}{lim} \frac{(f(x))^2-9}{\sqrt{|x-5|}} = 0. Then \underset{x \rightarrow 5}{lim} f(x) equals :
(a) 0
(b) 1
(c) 2
(d) 3

Answers

Answered by Brâiñlynêha
1

Hey mate..

ur answer is..

option A

0

hope it's help uh

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