Let f:R to R be a function by f(x)= x-1/x-2 then f is
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Answer:
f(0)=0 & f(x) is odd.
Further, if x>0 then
f(x)=
x+
x
1
1
∈(0,
2
1
]
Hence, f(x)∈[−
2
1
,
2
1
]
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