Math, asked by satyark67981, 1 year ago

Let f : R \rightarrow R be a differentiable function such that f(0) = 0, f(\frac{\pi}{2}) = 3, f^{'}(0) = 1. If g(x) = \int\limits^\frac{\pi}{2} _x {[f' (t)cosec \ t - cot \ t \ cosec \ t f(t)]} \, dt for x \in \bigg \lgroup 0, \frac{\pi}{2} \bigg ], then \underset{{x \to 0}}{\lim} g(x) =

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Answered by brunoconti
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Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST

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