let f (x)={0,if x is a rational,x,if x is a irrational and g (x)=0,if x is irrational, x,if x is rational
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Step-by-step explanation:
At x=0
x→0
+
lim
f(x)=0
(Same for rational and irrational)
Also
x→0
−
lim
f(x)=0
So it is continuous at x=0
At other number it's limit is not defined in it's neighbourhood as it can be x or 0 when x
=0 it is not continuous.
So f(x) is continuous only at 0
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