Question

Let f(x)=1/2+2/3cosec^2x+3/8sec^2x. the least value of f(x) for all permissible values of x?​

Answer 1

Answer:

37 / 24

Step-by-step explanation:

the ans is  1/2 + 2/3 + 3/8 = 37 /24

since sinx  ranges from [ -1 , 1 ]

      cos ranges from [ -1 , 1 ]

convert cosec and sec into sin and cos  , so the min values is 1