Computer Science, asked by debasishbiswal678, 1 month ago

let f(x)= 1-cos4x÷x²,x<0
a. ,x=0
\sqrt{x}÷ \sqrt{16+ \sqrt{x}}-4,x>0
determine the value of 'a' if f(x) is continuous.



Answers

Answered by saipunya901
1

Answer:

answer is 8

Explanation:

since the function is continues at x=0

lim f(x) = lim f(x)=f(a)

lim f(x)= lim 1-cos 4x/x²

=lim (2sin² 2x/(2x)²). 4 = 8

lim f(x)= lim \sqrt{x} \\\sqrt{(16+\sqrt{x} )} -4

= lim \sqrt{(16+\sqrt{x} )} +4 =8

also f(0) = 8

Hence ,a =8

Hope It's Helpful

Similar questions