Let f(x)=1 over x+2 ,find f(0),f(2) and f(3)
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3
Answer:
Given:-f(0)=2,f(1)=3
f(x+2)=2f(0)−f(x+1)
Put,x=0
f(2)=2f(0)−f(1)
f(2)=4−3=1
f(2)=2f(0)−f(2+1)
f(3)=2f(0)−f(2)
f(3)=4−1
f(3)=3
Put,x=2
f(4)=2f(2)−3
f(4)=1
Put,x=3
f(5)=2f(3)−f(3+1)
f(5)=4−1=3
Answered by
0
here f(x)=x+2
f(0)=0+2=2
f(2)=2+2=4
f(3)=3+2=5
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