let f(x) = 1/ underroot x+|x| then domain of f is
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Step-by-step explanation:
F(x) = 1/√{x - |x | }
for defining of function ,
x - | x | > 0
when, x > 0
x - x >0
0 > 0 this isn't true so,
x €empty
when, x < 0
x + x > 0
x > 0 this is also not possible so,
x€ empty
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