let f(x)=2x square and g(x)=x square/3 find fof and gog
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the answer is
Step-by-step explanation:
f(x)=x2+3x+1,g(x)=2x−3
(i) fog=f(g(x))=f(2x−3)=(2x−3)2+3(2x−3)+1
=4x2+9−12x+6x−9+1
∴fog=4x2−6x+1
(ii) gof=g(f(x))=g(x2+3x+1)=2(x2+3x+1)−3
=2x2+6x+2−3
∴gof=2x2+6x−1
(iii) fof=f(f(x))=f(x2+3x+1)=(x2+3x+1)2+3(x2+3x+1)+1
=x4+9x2+1+6x2+6x+2x2+3x2+9x+3+1
∴fof=x4+6x3+14x2+15x+5
(iv) gog=g(g(x))=g(2x−3)=2(2x−3)−3
=4x−6−3
∴gog=4x−9.
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