Let f(x) = 2x2 + x – 6
(A) f'(x)
(B) Find the value of x for which f′(x) = 0.
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Answer:
f(x) 2*2 + x - 6
so f'(x) = 2*2 +x - 6
then value of x:
2*2 +x - 6 =0
4 + x - 6 =0
x - 2 =0
x = 2
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