Math, asked by Soldier345, 5 months ago

Let f(x) = 2x2 + x – 6
(A) f'(x)
(B) Find the value of x for which f′(x) = 0.

Answers

Answered by shelendra2007
0

Answer:

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Answered by Priyankagahlawat
2

Answer:

f(x) 2*2 + x - 6

so f'(x) = 2*2 +x - 6

then value of x:

2*2 +x - 6 =0

4 + x - 6 =0

x - 2 =0

x = 2

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