let f(x) =3x-4 and g(x) x²+3x,find g(1)
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Given, f(x) = x2 + 3x - 4 and g(x) = x + 5.
We have to find f(x) . g(x)
f(x) . g(x) = (x2 + 3x - 4) (x + 5)
Using the multiplicative distributive property
f(x) . g(x) = x3 + 5x2 + 3x2 + 15x - 4x - 20
So we get
f(x) . g(x) = x3 + 8x2+ 11x - 20
Therefore, f(x) . g(x) is x3 + 8x2+ 11x - 20.
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