let f(x)= 3x²-x+5 find f(x-1)
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Answer:
f(x-1)=3(3x^2-6x+5)
Explanation:
f(x)=(3x)^2-x+5
f(x-1)=(3(x-1))^2-(x-1)+5
f(x-1)=(3x-3)^2-x+6
f(x-1)=9x^2+9-2(3x)(3)-x+6
f(x-1)=9x^2-18x+15
f(x-1)=3(3x^2-6x+5)
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