Let f(x) be a cubic polynomial with leading coefficient unity such that f(a) = b
and f'(a)=f''(a)=0. Suppose g(x)=f(x)-f(a)
+(a-x)f'(x)+3(x-a)^ 2 for which conclusion of Rolle’s theorem in [a, b] holds at x = 2, where x ∈(a,b)
1. The value of f''(2) , is
A) a prime number B) a composite number
C) an even number D) an odd number
52. The value of definite integral ∫ (a to b) f(x) is p/q
(where p & q are relatively prime numbers), then :
A) p+q=385 B)p-5q=51 C)p+q=6 D)p-5q=5
Answers
Answered by
4
Answer:
1. A
Step-by-step explanation:
i dont know the else left one
Answered by
1
given that,
, is equal to two times the root of then
therefore because the leading coefficient
as we know,
∴
, let's sub this value in equation1
let's sub as then, and the equation will be
∴
therefore, 6 is an even number and the correct option is (c) and the correct value of definite integral ∫ (a to b) f(x) is p/q is an option (c)p+q=6
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