Let f(x) be a polynomial such that 2f(x)+f(2-x)=5+x for any real number x. Find the value of f(0)+f(2)
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Given, f(2−x)=f(2+x)..(i)
∴f(x) is symmetric about x=2
f(20−x)=f(x)..(ii)
x→x+10
f(10−x)=f(10+x)
f(x) is symmetric about x=10
x→x+2
f(18−x)=f(x+2)..(ii)
f(2−x)=f(18−x)
x→−x
f(2+x)=f(18+x)
∴x+2→x
∴f(x)=f(x+16)
f(x) has period = 16
f(x)=5,x∈[0,170]
put x=2 in (i) f(0)=f(4)
put x=4 in (ii) f(4)=f(16)
when x∈[0,16]→f(x) has two solution
when x∈[0,160] has 20 solution.
When xin[0,170] has
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21
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solution
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