Let f(x) = e-* VX E[-1, 1) then
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f(x)=xe
x(x−1)
⇒f
′
(x)=e
x(1−x)
+x
2
(−1)e
x(1−x)
+x(1−x)e
x(1−x)
=−e
x(1−x)
(2x
2
−x−1)=−e
x(1−x)
(x−1)(x+1/2)
f
′
(x)=0 at x=−1/2,1 and f
′
(x)>0 when −1/2<x<1
⇒f(x) is increasing function on [−1/2,1]
I hope it's helpful for you
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