Question

Let f(x)=x^2 and g(x)=x^3-4 then the derivative of f(g(x)) will be

Answer 1

Answer:

$f(g(x)) = {x}^{6} - 8 {x}^{3} + 16$

Step-by-step explanation:

Let f(x) = x² and g(x) = x³ - 4

$\therefore \: f(g(x)) = {( {x}^{3} - 4) }^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{6} - 8 {x}^{3} + 16$

HOPE IT'LL HELP... :)