Question

Let f(x) = { x 2 , when 0 ≤ x ≤ 2 2x, when 2 ≤ x ≤ 5 } g(x) = { x 2 , when 0 ≤ x ≤ 3 2x, when 3 ≤ x ≤ 5 } Show that f is a function while g is not a function.

Answer 1

Answer:

prove the limitation and functional value

if both value equal then is a function

simple question

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