let f (x) = x square, g (x) = x-2, and h(x) = 1/x. evaluate:( no. 1) f(h(2)),(no. 2) f(g(2)).
Attachments:
Answers
Answered by
1
Answer:
B
Step-by-step explanation:
Correct option is
B
2
2
We know that h(x)=
g(x)
f(x)
=
(x−
x
1
)
x
2
+
x
2
1
=
(x−
x
1
)
(x−
x
1
)
2
+2
h(x)=(x−
x
1
)+
(x−
x
1
)
2
Applying AM≥GM we get
2
(x−
x
1
)+
(x−
x
1
)
2
≥
(x−
x
1
).
(x−
x
1
)
2
Solving the above inequality, we get
(x−
x
1
)+
(x−
x
1
)
2
≥2
2
Thus, the local minimum value of h(x) is 2
2
Answered by
4
refer the attachment
Step-by-step explanation:
hope it is helpful
Attachments:
Similar questions