Math, asked by azharulimaanansari, 1 day ago

let f (x) = x square, g (x) = x-2, and h(x) = 1/x. evaluate:( no. 1) f(h(2)),(no. 2) f(g(2)).​

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Answers

Answered by LenaMohanan2009
1

Answer:

B

Step-by-step explanation:

Correct option is

B

2  

2

 

We know that h(x)=  

g(x)

f(x)

=  

(x−  

x

1

)

x  

2

+  

x  

2

 

1

 

 

=  

(x−  

x

1

)

(x−  

x

1

)  

2

+2

 

h(x)=(x−  

x

1

)+  

(x−  

x

1

)

2

 

Applying  AM≥GM we get

2

(x−  

x

1

)+  

(x−  

x

1

)

2

 

≥  

(x−  

x

1

).  

(x−  

x

1

)

2

 

 

Solving the above inequality, we get

(x−  

x

1

)+  

(x−  

x

1

)

2

≥2  

2

 

Thus, the local minimum value of h(x) is 2  

2

Answered by sahanasusil83
4

refer the attachment

Step-by-step explanation:

hope it is helpful

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