Math, asked by roy179266, 7 months ago

Let f(x) = x2 + 1 and g(x) = 3x + 1, then g(f(x)) is
(a) 3x2 + 1

(b) 3x2 + 2

(c) 3x2 + 4

(d) (3x + 1)2 + 1

Answers

Answered by Anonymous

$\huge\underline\mathfrak\pink{ Hello~Mate }$

$<font color="blue">$

=>g(f(x))

=>g(x²+1)

here g(x)=3x+1

now

=>g(x²+1)=3(x²+1)+1

=3x²+3+1

=3x²+4

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Answered by BrainlyConqueror0901

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{g(f(x))=3x^{2}+4}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt:\implies f(x) = {x}^{2} + 1 \\ \\ \tt:\implies g(x) = 3x + 1 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies g(f(x)) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies g(f(x)) =g( {x}^{2} + 2) \\ \\ \tt: \implies g(f(x)) = 3( {x}^{2} + 1) + 1 \\ \\ \tt: \implies g(f(x)) =3 {x}^{2} + 3 + 1 \\ \\ \green{\tt: \implies g(f(x)) = {3x}^{2} + 4}$

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Let f(x) = x2 + 1 and g(x) = 3x + 1, then g(f(x)) is(a) 3x2 + 1(b) 3x2 + 2(c) 3x2 + 4(d) (3x + 1)2 + 1​

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• According to given question :

Let f(x) = x2 + 1 and g(x) = 3x + 1, then g(f(x)) is
(a) 3x2 + 1

(b) 3x2 + 2

(c) 3x2 + 4

(d) (3x + 1)2 + 1