Question

let f(x)=x² and g(x)=2x+1 are two real functions. find (f+g)(x),(f-g)(x) and (fg)(x)​

Answer 1

Answer:

ANSWER:-

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)

=x

2

+2x+1

(f−g)(x)=f(x)−g(x)

=x

2

−(2x+1)

=x

2

−2x−1

(fg)(x)=f(x).g(x)

=x

2

(2x+1)

=2x

3

+x

2

(

g

f

)(x)=

g(x)

f(x)

(g(x)

=0)

=

2x+1

x

2

(x

=−

2

1

)

Answer 2

(f+g)(x)=f(x)+g(x)

=x²+2x+1

(f−g)(x)=f(x)−g(x)

=x²−(2x+1)

=x²−2x−1

(fg)(x)=f(x).g(x)

=x²(2x+1)

=2x³+x²

$( \frac{f}{g})(x)= \frac{f(x)}{g(x)} (g(x)≠0)$

$= \frac{ {x}^{2} }{2x + 1}$

(x≠-½)