Let f : X → Y and g : Y → Z be two invertible functions. Then gof is alsoinvertible with (gof)
–1 = f–1og–1
.
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Proof To show that gof is invertible with (gof)
–1 = f–1og–1, it is enough to show that
(f–1og–1)o(gof) = IX and (gof)o(f–1og–1) = IZ
.Now, (f–1og–1)o(gof) = ((f–1og–1) og) of, by Theorem 1
= (f–1o(g–1og)) of, by Theorem 1
= (f–1 o IY) of, by definition of g
–1= IX
.Similarly, it can be shown that (gof ) o (f –1 o g –1) = IZ
.
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