Question

Let f(x+y)= f(x) . f(y) , f(5) = 2, f'(0) = 3 ( where x and y are natural number) then what is the value of f'(5) = ?​

Answer 1

Answer: f'(5)= 0

Step-by-step explanation:

given: f(5) = 2

since we know that the differentiation of any constant with respect to any variable is equal to zero.

Thus, f'(5)=0 ( because f(5) = 2 is a constant).

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