Question

Let f : Z->Z defined by f( x) = x+1 .then range of function f is *​

Answer 1

Answer:

Correct option is D)

Let f:Z↦Z be defined as f(x)=x

2

,x∈Z.

We know that the square of an integer is always a unique integer.

So, ''f'' is a function.

Now, since f(−2)=f(2)=4, ''f'' is not an injection.

There is no integer x∈Z:f(x)=−1.

Hence , ''f'' is not a surjection.

Since ''f'' is neither one-one nor onto, ''f'' is not a bijection.