Question

Let five geometric means are inserted between 32/3 and 243/2
then find sum of all the geometric
means.​

Answer 1

Answer:

211

Step-by-step explanation:

Let five geometric means are inserted between 32/3 and 243/2

then find sum of all the geometric

means.

GP becomes

a ar ar^2 ar^5 ar^6

a = 32/3 ar^6 = 243/2

r is common ration

ar to ar^5 are 5 geometric mean inserted

ar^6 / a = (243/2)/(32/3)

r^6 = 729/64

r^6 = 3^6/2^6

r = 3/2

ar = (32/3)*(3/2) = 16

GP of geometric mean

16 , 16×3/2 , 16 ×(3/2)^2 , 16×(3/2)^3 , 16×(3/2)^4

a = 16 r = 3/2 n = 5

Sum =.a (r^n -1)/(r-1)

= 16 ((3/2)^5 - )/(3/2 -1)

= 16 (243/32 - 1) /(1/2)

= 32 ( 211/32)

= 211

Answer 2

Answer:

MArk me brainy teachet