Let G 5 Z18 and let H 5 k6l 5 {0, 6, 12}. Then G/H 5
{0 1 H, 1 1 H, 2 1 H, 3 1 H, 4 1 H, 5 1 H}. To illustrate how the
group elements are combined, consider (5 1 H) 1 (4 1 H). This
should be one of the six elements listed in the set G/H
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