Question

Let G = {(a,b) belong to R , b is not equal to 0}. Define a binary
operation on G by (a,b). (C, d) = [a+bc, bd].
Show that
(G ) is a non- abelian
group​

Answer 1

Step-by-step explanation:

We just have to show that it is non-abelian for a case. Here, for b = 1 it is undefined. So G is non-abelian.