Let G and C be the events t t the chosen
student is a genius and a ch colate lover
respectively. Let P(G)=0.6,1 C)=0.7 and
P(
GC) = 0.4 then P(G' C') = ...
(A) 0.1
(B) 0.9
(C) 0.6
(D) 0.3
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It has given that, G and C are the events of students who are genius and chocolate lovers respectively. Here P(G) = 0.6, P(C) = 0.7 and P(G U C) = 0.4
We have to find the P(G' U C')
solution : we know, P(G' U C') = 1 - P(G n C)
= 1 - [P(G) + P(C) - P(G U C) ]
= 1 - [0.6 + 0.7 - 0.4 ]
= 1 - [0.9 ]
= 0.1
therefore the value of P(G' U C') = 0.1
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