Chemistry, asked by MouniRoy7645, 6 months ago

Let hydrolysis constant (Kh) of NH_4^+ be y. Then equilibrium constant (Ka) for conjugate acid of NH3 at 25°C is: (a) 1/y×10^(-14) (b) 10^(-14) (c) y (d) y×10^(-14)

Answers

Answered by mannatssingh9a5hhps2
1

Answer:

11th

Chemistry

Equilibrium

Hydrolysis of Salts and the pH of their Solutions

The dissociation constant o...

CHEMISTRY

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Asked on December 30, 2019 by

Eswar Vishwavani

The dissociation constant of NH

4

OH is 1.8×10

−5

. The hydrolysis constant of NH

4

+

ions at 25

0

C would be:

MEDIUM

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ANSWER

The relationship betwen the hydrolysis constant of the salt ammonium chloride and the base dissociation constant of ammonia is as given below:

K

h

=

K

b

K

w

Substituting values in the above expression, we get:

K

h

=

1.8×10

−5

1×10

−14

=5.556×10

−10

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