Question

Let I[y(x)] = [[y(x)]² dx be a functional then for y₁(x) = sin(x), 1[y₁ (x)] =
(A) π/2
(B) π/4
(C) 0
(D) 2π​

Answer 1

Answer:

$2\pi$

Step-by-step explanation:

if it is wrong I don't know