Question

Let k be an integer such that the triangle with vertices (k. - 3k).(5,k) and (k, 2) has area 28
sq. units. Then, the orthocentre of this triangle is at the point.
a) (2,-1/2)
b) (1,3/4)
c) (1,-3/4)
d) (2,1/2)

Answer 1

Answer:

option D 2,1/2 ans

Step-by-step explanation:

HOPE IT HELPS

MARK BRAINS

Answer 2

Answer:

The orthocentre of this triangle is at the point (2,1/2)

Step-by-step explanation:

Given,  

Given vertices are triangle are (k, - 3k), (5,k) and (-k, 2)

Step 1:

We have (3 X 3 matrix)

| k 3k 1 |

Step 2:

(1/2) | 5  k 1 |= 28

Step 3:

| k 2  1 |

5k2 + 13k – 46 = 0

or

5k2 + 13k + 66 = 0 (no real solution exist)

Step 4:

k =–23/5 or k = 2

As k is an integer, so k=2

Orthocentre is (2, 1/2)

Hence Proved.