Let K be the largest number with exactly 3 factors that divide 25! How many factors does (k – 1) have?
16
12
9
14
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If and only if the total no. of factors of an integer is an odd number, then the integer will be a perfect square.
Here the integer k has exactly 3 factors, so we can say that k is a perfect square, and those three factors will be,
1, √k, k
Here, √k should be a prime number.
In 25!, numbers 11 and 22 are multiplied, so there will be 11² = 121 divides 25!.
Only 13 is multiplied in 25! but not 26 and other multiplies of 13. So 13² = 169 does not divide 25!.
Thus we can say that k = 121.
⇒ k - 1 = 120
120 = 2³ × 3 × 5
So the total no. of factors of 120 = (3 + 1)(1 + 1)(1 + 1) = 4 × 2 × 2 = 16.
Hence 16 is the answer.
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