Let L be a normal to the parabola y² = 4x. If L passes through the point (9, 6), then L is given by
(a) y – x + 3 = 0
(b) y + 3x – 33 = 0
(c) y + x – 15 = 0
(d) y – 2x + 12 = 0
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Step-by-step explanation:
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Option (b), y + 3x - 33 = 0 is correct.
Step-by-step explanation:
The given parabola is
y² = 4x
Differentiating both sides with respect to x, we get
2y dy/dx = 4
or, dy/dx = 2/y
Now dy/dx at the point (9, 6) = 2/6 = 1/3
So the slope of the normal is given by
m = (- dx/dy) at the point (9, 6)
= - 3
Using the point-slope formula, where the point is (9, 6) and the slope of the normal being (- 3), we get the required straight line as
y - 6 = (- 3) (x - 9)
or, y - 6 = - 3x + 27
or, y + 3x - 33 = 0
Thus option (b) is correct.
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