Question

let l be the length of one side of a triangle . another side of a triangle is 5 less than l . the longest side of the triangle is seven times the shortest . write the perimeter of the triangle in term of l

Answer 1

hiii!!!

here's ur answer...

L IS ONE OF THE SODE OF THE TRIANGLE.

ANOTHER SIDE IS 5 LESS THAN L.

THEREFORE IT WILL BE = L - 5

NOW, THE LONGEST SIDE IS SEVEN TIMES THE SHORTEST.

HERE SHORTEST IS L - 5.

SO THE LONGEST SIDE WILL BE = 7 ( L - 5 )

= 7L - 35

PERIMETER OF THE TRIANGLE = sum of all sides

= L + ( L - 5 ) + ( 7L - 35 )

= L + L - 5 + 7L - 35

= L + L + 7L - 5 - 35

= 9L - 40 UNITS

hope this helps u..!!

Answer 2

1st side= l
2nd side = l-5
3rd side= 7(l-5) this is because 2nd is the shortest side
Perimeter of ∆= l+(l-5)+(7l-35)
= l+l-5+7l-35 = 9l-40
Hope it helped