Let l, r, c and v represent inductance, resistance, capacitance and voltage, respectively. The dimension of 1/rcv
in SI units will be :
(A) [LA⁻² ]
(B) [A⁻¹ ]
(C) [LTA] (D) [LT² ]
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Explanation:
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Answered by
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Answer:
energy= 1/2 Li²
[L] = [ energy]/[ i²] = [M¹L²T-²]/[A²] = [M¹L²T-²A-²]
[R]= [ volt/ current] = [ ML²T-³A-²]
[C] = [ charge/ volt] = [ M-¹L-²T⁴A²]
[V] = [ resistance × time] = [M¹L-²T-³A-¹]
L/RCV= [M¹L²T-²A-²]/ [ ML²T-³A-²] [ M-¹L-²T⁴A²] [M¹L-²T-³A-¹]
therefore, L/RCV= [M⁰L⁰T⁰A-¹]
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